# Realistic Math Problems Help 6th-graders Solve Real-Life Questions

Solving math problems can intimidate sixth-graders: It shouldn t. Using a few simple formulas and a bit of logic can help students quickly calculate answers to seemingly intractable problems. Explain to students that you can find the rate (or speed) that someone is traveling if you know the distance and time that she traveled. Conversely, if you know the speed (rate) that a person is traveling as well as the distance, you can calculate the time he traveled. You simply use the basic formula: rate times the time equals distance, or r * t d (where * is the symbol for times.)

The free, printable worksheets below involve problems such as these, as well as other important problems, such as determining the largest common factor, calculating percentages, and more. The answers for each worksheet are provided through a link in the second slide right after each worksheet. Have students work the problems, fill in their answers in the provided blank spaces, then explain how they would arrive at the solutions for questions where they are having difficulty. The worksheets provide a great and simple way to do quick formative assessments for an entire math class.

### Worksheet No 1

On this PDF, your students will solve problems such as: Your brother traveled 117 miles in 2.25 hours to come home for school break. What’s the average speed that he was traveling? and You have 15 yards of ribbon for your gift boxes. Each box gets the same amount of ribbon. How much ribbon will each of your 20 gift boxes get?

### Worksheet No. 1 Solutions

To solve the first equation on the worksheet, use the basic formula: rate times the time distance, or r * t d. In this case, r the unknown variable, t 2.25 hours, and d 117 miles. Isolate the variable by dividing r from each side of the equation to yield the revised formula, r t ÷ d. Plug in the numbers to get: r 117 ÷ 2.25, yielding r 52 mph.

For the second problem, you don t even need to use a formula—just basic math and some common sense. The problem involves simple division: 15 yards of ribbon divided by 20 boxes, can be shortened as 15 ÷ 20 0.75. So each box gets 0.75 yards of ribbon.